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diff src/Predicates.v @ 280:15f49309c371
PC's Chapter 4 comments
author | Adam Chlipala <adam@chlipala.net> |
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date | Tue, 12 Oct 2010 09:30:17 -0400 |
parents | c4b1c0de7af9 |
children | 4146889930c5 |
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--- a/src/Predicates.v Fri Oct 01 14:19:20 2010 -0400 +++ b/src/Predicates.v Tue Oct 12 09:30:17 2010 -0400 @@ -112,7 +112,7 @@ ]] - We see that [not] is just shorthand for implication of [False]. We can use that fact explicitly in proofs. The syntax [~P] expands to [not P]. *) + We see that [not] is just shorthand for implication of [False]. We can use that fact explicitly in proofs. The syntax [~ P] expands to [not P]. *) Theorem arith_neq' : ~ (2 + 2 = 5). (* begin thide *) @@ -498,10 +498,21 @@ ]] - What on earth happened here? Internally, [destruct] replaced [1] with a fresh variable, and, trying to be helpful, it also replaced the occurrence of [1] within the unary representation of each number in the goal. This has the net effect of decrementing each of these numbers. If you are doing a proof and encounter a strange transmutation like this, there is a good chance that you should go back and replace a use of [destruct] with [inversion]. *) + What on earth happened here? Internally, [destruct] replaced [1] with a fresh variable, and, trying to be helpful, it also replaced the occurrence of [1] within the unary representation of each number in the goal. This has the net effect of decrementing each of these numbers. *) Abort. +(** To see more clearly what is happening, we can consider the type of [isZero]'s induction principle. *) + +Check isZero_ind. +(** %\vspace{-.15in}% [[ +isZero_ind + : forall P : nat -> Prop, P 0 -> forall n : nat, isZero n -> P n + + ]] + + In our last proof script, [destruct] chose to instantiate [P] as [fun n => S n + S n = S (S (S (S n)))]. You can verify for yourself that this specialization of the principle applies to the goal and that the hypothesis [P 0] then matches the subgoal we saw generated. If you are doing a proof and encounter a strange transmutation like this, there is a good chance that you should go back and replace a use of [destruct] with [inversion]. *) + (* begin hide *) (* In-class exercises *) @@ -716,7 +727,7 @@ ]] - We are already sunk trying to prove the first subgoal, since the argument to [even] was replaced by a fresh variable internally. This time, we find it easiest to prove this theorem by way of a lemma. Instead of trusting [induction] to replace expressions with fresh variables, we do it ourselves, explicitly adding the appropriate equalities as new assumptions. *) + We are already sunk trying to prove the first subgoal, since the argument to [even] was replaced by a fresh variable internally. This time, we find it easier to prove this theorem by way of a lemma. Instead of trusting [induction] to replace expressions with fresh variables, we do it ourselves, explicitly adding the appropriate equalities as new assumptions. *) Abort. @@ -738,12 +749,11 @@ ]] - At this point it is useful to use a theorem from the standard library, which we also proved with a different name in the last chapter. *) + At this point it is useful to use a theorem from the standard library, which we also proved with a different name in the last chapter. We can search for a theorem that allows us to rewrite terms of the form [x + S y]. *) - Check plus_n_Sm. + SearchRewrite (_ + S _). (** %\vspace{-.15in}% [[ - plus_n_Sm - : forall n m : nat, S (n + m) = n + S m + plus_n_Sm : forall n m : nat, S (n + m) = n + S m ]] *) rewrite <- plus_n_Sm in H0. @@ -911,7 +921,7 @@ end ]] #</li># %\item%#<li># You probably do not want to use an inductive definition for compatibility of variable assignments and typings.#</li># - %\item%#<li># The [Tactics] module from this book contains a variant [crush'] of [crush]. [crush'] takes two arguments. The first argument is a list of lemmas and other functions to be tried automatically in "forward reasoning" style, where we add new facts without being sure yet that they link into a proof of the conclusion. The second argument is a list of predicates on which inverison should be attempted automatically. For instance, running [crush' (lemma1, lemma2) pred] will search for chances to apply [lemma1] and [lemma2] to hypotheses that are already available, adding the new concluded fact if suitable hypotheses can be found. Inversion will be attempted on any hypothesis using [pred], but only those inversions that narrow the field of possibilities to one possible rule will be kept. The format of the list arguments to [crush'] is that you can pass an empty list as [tt], a singleton list as the unadorned single element, and a multiple-element list as a tuple of the elements.#</li># + %\item%#<li># The [Tactics] module from this book contains a variant [crush'] of [crush]. [crush'] takes two arguments. The first argument is a list of lemmas and other functions to be tried automatically in "forward reasoning" style, where we add new facts without being sure yet that they link into a proof of the conclusion. The second argument is a list of predicates on which inversion should be attempted automatically. For instance, running [crush' (lemma1, lemma2) pred] will search for chances to apply [lemma1] and [lemma2] to hypotheses that are already available, adding the new concluded fact if suitable hypotheses can be found. Inversion will be attempted on any hypothesis using [pred], but only those inversions that narrow the field of possibilities to one possible rule will be kept. The format of the list arguments to [crush'] is that you can pass an empty list as [tt], a singleton list as the unadorned single element, and a multiple-element list as a tuple of the elements.#</li># %\item%#<li># If you want [crush'] to apply polymorphic lemmas, you may have to do a little extra work, if the type parameter is not a free variable of your proof context (so that [crush'] does not know to try it). For instance, if you define a polymorphic map insert function [assign] of some type [forall T : Set, ...], and you want particular applications of [assign] added automatically with type parameter [U], you would need to include [assign] in the lemma list as [assign U] (if you have implicit arguments off) or [assign (T := U)] or [@assign U] (if you have implicit arguments on).#</li># #</ol> </li>#%\end{enumerate}%