diff src/Coinductive.v @ 200:df289eb8ef76

Small fixes while reading student solutions
author Adam Chlipala <adamc@hcoop.net>
date Fri, 02 Jan 2009 08:57:25 -0500
parents 32a5ad6e2bb0
children 8caa3b3f8fc0
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--- a/src/Coinductive.v	Mon Dec 01 08:32:20 2008 -0500
+++ b/src/Coinductive.v	Fri Jan 02 08:57:25 2009 -0500
@@ -467,7 +467,7 @@
   %\item%#<li># Define a function [map] for building an output tree out of two input trees by traversing them in parallel and applying a two-argument function to their corresponding data values.#</li>#
   %\item%#<li># Define a tree [falses] where every node has the value [false].#</li>#
   %\item%#<li># Define a tree [true_false] where the root node has value [true], its children have value [false], all nodes at the next have the value [true], and so on, alternating boolean values from level to level.#</li>#
-  %\item%#<li># Prove that [true_falses] is equal to the result of mapping the boolean "or" function [orb] over [true_false] and [falses].  You can make [orb] available with [Require Import Bool.].  You may find the lemma [orb_false_r] from the same module helpful.  Your proof here should not be about the standard equality [=], but rather about some new equality relation that you define.#</li>#
+  %\item%#<li># Prove that [true_false] is equal to the result of mapping the boolean "or" function [orb] over [true_false] and [falses].  You can make [orb] available with [Require Import Bool.].  You may find the lemma [orb_false_r] from the same module helpful.  Your proof here should not be about the standard equality [=], but rather about some new equality relation that you define.#</li>#
 #</ol>#%\end{enumerate}% #</li>#
 
 #</ol>#%\end{enumerate}% *)